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2009-11-10 22:15 Justice

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    If x and y are positive integers, find the number of integers between x(y+2007) and xy?  




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2009-11-10 22:20 ZGF-2107
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2009-11-10 22:23 Justice

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2009-11-10 22:36 Justice
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If x and y are positive integers, find the number of integers between x(y+2007) and xy?

2009-11-10 22:40 receition
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2009-11-10 22:46 �s��
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2009-11-10 22:50 receition
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2009-11-10 22:59 receition

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2009-11-10 23:24 satzuna
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2009-11-10 23:30 satzuna
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2009-11-11 01:05 satzuna
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2009-11-11 01:12 Zerco
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2009-11-11 19:05 s041161
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2009-11-11 19:10 Justice

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2009-11-11 19:37 s041161
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integer ge�ƥ�=x(y+2007)-xy+1
                     =2007x+1
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2007x+1-2=2007x-1

2009-11-11 21:10 edmondlau007
x(y+2007)-xy-1
=xy+2007x-xy-1
=2007x-1

when ,B>A,the number between A and B is  B-A-1

2009-11-11 22:00 �u��
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2010-6-14 18:23 �դ�M
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2010-6-14 20:19 s35op32
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y>0
y+2007>2007
so x(y+2007)>2007x

as x>0
by deducting the repeated one(?),
thus, the answer is 2007x-1.

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2010-6-15 17:56 chronos
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