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2009-11-10 22:15
Justice
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If x and y are positive integers, find the number of integers between x(y+2007) and xy?
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2009-11-10 22:20
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2009-11-10 22:23
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2009-11-10 22:30
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2009-11-10 22:30
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2009-11-10 22:33
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2009-11-10 22:36
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If x and y are positive integers, find the number of integers between x(y+2007) and xy?
2009-11-10 22:40
receition
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2009-11-10 22:46
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x(y+2007) - xy = 2007x
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2009-11-10 22:50
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2009-11-10 22:56
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2009-11-10 22:59
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2009-11-10 23:24
satzuna
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2009-11-10 23:27
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���N�Ox(y+2007) - xy
= xy + 2007x - xy
= 2007x
2009-11-10 23:30
satzuna
[quote]�쩫�� [i]�s��[/i] �� 2009-11-10 23:27 �o��
���N�Ox(y+2007) - xy
= xy + 2007x - xy
= 2007x [/quote]
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2009-11-10 23:44
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2009-11-11 01:05
satzuna
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2009-11-11 01:12
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2009-11-11 19:05
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2009-11-11 19:10
Justice
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2009-11-11 19:37
s041161
��x(y+2007)�h��xy,�sxy�Px(y+2007)�O���integer���pge��...
integer ge�ƥ�=x(y+2007)-xy+1
=2007x+1
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2007x+1-2=2007x-1
2009-11-11 21:10
edmondlau007
x(y+2007)-xy-1
=xy+2007x-xy-1
=2007x-1
when ,B>A,the number between A and B is B-A-1
2009-11-11 22:00
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2010-6-14 18:23
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2010-6-14 20:19
s35op32
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y>0
y+2007>2007
so x(y+2007)>2007x
as x>0
by deducting the repeated one(?),
thus, the answer is 2007x-1.
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2010-6-15 17:56
chronos
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