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<p>#1 又一題新野- -<br /><small>why?<br />
[(1+3i)/(1-2i)]^20={開方2(cos135+i sin135)}^20-----a<br />
                         =開方2^20{cos(135x20)+i sin(135x20)}<br />
                         =開方2^20(cos180+i sin180)----b<br />
                         =開方2^20(-1)<br />
                         =-1024<br />
a到b點做= =?好唔明<br />
又一題新野要問<br />
3^2x=81x<br />
(2x-4)log3=logx<br />
            : <br />
            :<br />
下面點計有冇人識?<br />
<br />
[[i] 本帖最後由 星馬 於 2009-4-10 20:04 編輯 [/i]]</small><br />
3/10 18:20<br />
星馬<br /></p>
<p>#2 <br /><small>..</small><br />
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